25x^2-50x+32=0

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Solution for 25x^2-50x+32=0 equation:


Simplifying
25x2 + -50x + 32 = 0

Reorder the terms:
32 + -50x + 25x2 = 0

Solving
32 + -50x + 25x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
25 the coefficient of the squared term: 

Divide each side by '25'.
1.28 + -2x + x2 = 0

Move the constant term to the right:

Add '-1.28' to each side of the equation.
1.28 + -2x + -1.28 + x2 = 0 + -1.28

Reorder the terms:
1.28 + -1.28 + -2x + x2 = 0 + -1.28

Combine like terms: 1.28 + -1.28 = 0.00
0.00 + -2x + x2 = 0 + -1.28
-2x + x2 = 0 + -1.28

Combine like terms: 0 + -1.28 = -1.28
-2x + x2 = -1.28

The x term is -2x.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2x + 1 + x2 = -1.28 + 1

Reorder the terms:
1 + -2x + x2 = -1.28 + 1

Combine like terms: -1.28 + 1 = -0.28
1 + -2x + x2 = -0.28

Factor a perfect square on the left side:
(x + -1)(x + -1) = -0.28

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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